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How to: Add vertical & horizontal Median lines on scatte
Posted: Wed Dec 13, 2006 3:53 pm
by 9524907
Hello,
is it possible to have a scatter chart with a vertical & horizontal median lines? If so, can someone point us in the right direction?
The scatter is to determine how a person is performing against their peers.
Thanks!
Posted: Wed Dec 13, 2006 3:57 pm
by narcis
Hi ASM,
Yes, this can be done as shown in the What's New?\Welcome !\New Functions\Median Function example. This example can be found at the features demo available at TeeChart's program group.
Posted: Wed Dec 13, 2006 3:59 pm
by 9524907
Narcís
Thanks for the quick response!
Chris
ASM Research
Posted: Wed Dec 13, 2006 6:57 pm
by 9524907
we can get the horizontal median to display but how do we also display a vertical median to create a "crosshair".
Thanks!
Posted: Thu Dec 14, 2006 9:41 am
by narcis
Hi ASM,
Vertical median function doesn't exist. However, you can easily implement that using an horizontal line series like this:
Code: Select all
private void Form1_Load(object sender, EventArgs e)
{
tChart1.Aspect.View3D = false;
line1.FillSampleValues();
Steema.TeeChart.Styles.HorizLine vertMedian1 = new Steema.TeeChart.Styles.HorizLine(tChart1.Chart);
double xMedian;
if (line1.Count % 2 != 0)
xMedian = line1.XValues[(line1.Count / 2) + 1];
else
xMedian = (line1.XValues[(line1.Count / 2)] + line1.XValues[(line1.Count / 2) + 1]) / 2;
vertMedian1.Add(xMedian, line1.YValues.Minimum);
vertMedian1.Add(xMedian, line1.YValues.Maximum);
}
Posted: Thu Dec 14, 2006 12:57 pm
by narcis
Hi ASM,
Sorry but I noticed my initial algorithm was wrong, should be like this:
Code: Select all
private void Form1_Load(object sender, EventArgs e)
{
tChart1.Aspect.View3D = false;
line1.FillSampleValues();
Steema.TeeChart.Styles.HorizLine vertMedian1 = new Steema.TeeChart.Styles.HorizLine(tChart1.Chart);
double xMedian;
if (line1.Count % 2 == 0)
xMedian = line1.XValues[(line1.Count / 2)];
else
xMedian = (line1.XValues[(line1.Count / 2)] + line1.XValues[(line1.Count / 2) + 1]) / 2;
vertMedian1.Add(xMedian, line1.YValues.Minimum);
vertMedian1.Add(xMedian, line1.YValues.Maximum);
}
scatter chart line1 object
Posted: Fri Dec 15, 2006 8:55 pm
by 9524907
What sort of object is line1? Would you send the fully qualified objects to draw a line?
Posted: Fri Dec 15, 2006 9:57 pm
by 9524907
Also, can you post the VB.NET equivalent of the algorithm you gave? I am having trouble converting some of your declarations. For example, I can't do:
Dim vertMedian1 = As New Steema.TeeChart.Styles.HorizLine
Posted: Mon Dec 18, 2006 8:39 am
by narcis
Hi ASM,
I have converted C# code to VB.NET code using
Kamal Patel's conversor. You may also be interested in knowing of
Carlos Aguilar's conversor.
Code: Select all
Private Sub Form1_Load(ByVal sender As Object, ByVal e As EventArgs)
tChart1.Aspect.View3D = False
line1.FillSampleValues()
Dim vertMedian1 As Steema.TeeChart.Styles.HorizLine = New Steema.TeeChart.Styles.HorizLine(tChart1.Chart)
Dim xMedian As Double
If line1.Count % 2 = 0 Then
xMedian = line1.XValues((line1.Count / 2))
Else
xMedian = (line1.XValues((line1.Count / 2)) + line1.XValues((line1.Count / 2) + 1)) / 2
End If
vertMedian1.Add(xMedian, line1.YValues.Minimum)
vertMedian1.Add(xMedian, line1.YValues.Maximum)
End Sub
If the VB.NET code I posted doesn't work for you please let me know.