How to: Add vertical & horizontal Median lines on scatte

[ASM]

Hello,
is it possible to have a scatter chart with a vertical & horizontal median lines? If so, can someone point us in the right direction?

The scatter is to determine how a person is performing against their peers.

Thanks!

[Narcís]

Hi ASM,

Yes, this can be done as shown in the What's New?\Welcome !\New Functions\Median Function example. This example can be found at the features demo available at TeeChart's program group.

[ASM]

Narcís
Thanks for the quick response!

Chris
ASM Research

[ASM]

we can get the horizontal median to display but how do we also display a vertical median to create a "crosshair".

Thanks!

[Narcís]

Hi ASM,

Vertical median function doesn't exist. However, you can easily implement that using an horizontal line series like this:

Code: Select all

		private void Form1_Load(object sender, EventArgs e)
		{
			tChart1.Aspect.View3D = false;
			line1.FillSampleValues();

			Steema.TeeChart.Styles.HorizLine vertMedian1 = new Steema.TeeChart.Styles.HorizLine(tChart1.Chart);

			double xMedian;

			if (line1.Count % 2 != 0)
				xMedian = line1.XValues[(line1.Count / 2) + 1];
			else
				xMedian = (line1.XValues[(line1.Count / 2)] + line1.XValues[(line1.Count / 2) + 1]) / 2;

			vertMedian1.Add(xMedian, line1.YValues.Minimum);
			vertMedian1.Add(xMedian, line1.YValues.Maximum);
		}

[Narcís]

Hi ASM,

Sorry but I noticed my initial algorithm was wrong, should be like this:

Code: Select all

		private void Form1_Load(object sender, EventArgs e)
		{
			tChart1.Aspect.View3D = false;
			line1.FillSampleValues();

			Steema.TeeChart.Styles.HorizLine vertMedian1 = new Steema.TeeChart.Styles.HorizLine(tChart1.Chart);

			double xMedian;

			if (line1.Count % 2 == 0)
				xMedian = line1.XValues[(line1.Count / 2)];
			else
				xMedian = (line1.XValues[(line1.Count / 2)] + line1.XValues[(line1.Count / 2) + 1]) / 2;

			vertMedian1.Add(xMedian, line1.YValues.Minimum);
			vertMedian1.Add(xMedian, line1.YValues.Maximum);
		}

[ASM]

What sort of object is line1? Would you send the fully qualified objects to draw a line?

[ASM]

Also, can you post the VB.NET equivalent of the algorithm you gave? I am having trouble converting some of your declarations. For example, I can't do:

Dim vertMedian1 = As New Steema.TeeChart.Styles.HorizLine

[Narcís]

Hi ASM,

I have converted C# code to VB.NET code using Kamal Patel's conversor. You may also be interested in knowing of Carlos Aguilar's conversor.

Code: Select all

      Private  Sub Form1_Load(ByVal sender As Object, ByVal e As EventArgs)
         tChart1.Aspect.View3D = False
         line1.FillSampleValues()
 
         Dim vertMedian1 As Steema.TeeChart.Styles.HorizLine =  New Steema.TeeChart.Styles.HorizLine(tChart1.Chart) 
 
         Dim xMedian As Double
 
         If line1.Count % 2 = 0 Then
            xMedian = line1.XValues((line1.Count / 2))
         Else 
            xMedian = (line1.XValues((line1.Count / 2)) + line1.XValues((line1.Count / 2) + 1)) / 2
         End If
 
         vertMedian1.Add(xMedian, line1.YValues.Minimum)
         vertMedian1.Add(xMedian, line1.YValues.Maximum)
      End Sub

If the VB.NET code I posted doesn't work for you please let me know.